Answer:
Step-by-step explanation:
Let the number of Rs 50 notes and Rs 100 notes be x and y respectively.
According to the question, x + y = 25
(i) 50x + 100y = 2000
(ii) Multiplying equation (i) by 50, we get 50x + 50y = 1250
(iii) Subtracting equation (iii) from equation (ii), we get 50y = 750 y = 15
Putting this value in equation (i), we have x = 10 Hence, Meena has 10 notes of Rs 50 and 15 notes of Rs 100.
Let the number of rupees 50 and 100 notes = x + y
So, according to question
x + y = 25. ( 1 )
50 x + 100 y = 2000. ( 2 )
by elimination method we have
50 * x + y = 25
Subtracting equation 1 from 2
50x + 100y = 2000
50x + 50y = 1250
50y = 750
y = 15
x + y = 25 ( given)
x = 25-15
= 10
therefore there are 10 fifty rupee notes and 15 hundred rupee notes
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Answers & Comments
Answer:
Step-by-step explanation:
Let the number of Rs 50 notes and Rs 100 notes be x and y respectively.
According to the question, x + y = 25
(i) 50x + 100y = 2000
(ii) Multiplying equation (i) by 50, we get 50x + 50y = 1250
(iii) Subtracting equation (iii) from equation (ii), we get 50y = 750 y = 15
Putting this value in equation (i), we have x = 10 Hence, Meena has 10 notes of Rs 50 and 15 notes of Rs 100.
Answer:
Let the number of rupees 50 and 100 notes = x + y
So, according to question
x + y = 25. ( 1 )
50 x + 100 y = 2000. ( 2 )
by elimination method we have
50 * x + y = 25
Subtracting equation 1 from 2
50x + 100y = 2000
50x + 50y = 1250
50y = 750
y = 15
x + y = 25 ( given)
x = 25-15
= 10
therefore there are 10 fifty rupee notes and 15 hundred rupee notes