Solution :
Here , let us assume that the principal for the simple interest is Rs. x .
Now , the rate of the simple interest is 6 1/4 % per annum .
Rate :
> [ 24 + 1]/4 %
=> 25/4 % per annum .
Assume that the required number of years after the principal doubles to become twice of its amount is t years .
According to the question :
If the principal become twice itself :
=> Original Principal + SI for a certain number of years ] = 2 × Original Principal
=> Original Principal = SI for a certain number of years .
We took the original principal as Rs. x and the time as t
=> x = [ x • t • 25/4 ] / 100
=> x = [ x • t • 25/400 ]
=> x = [ x • t • 1/16 ]
=> 1 = t/16
=> t = 16 years .
Thus , the required time period is 16 years .
This is the answer .
___________________________________________
Answer:
⋆ Let, the principle be Rs x
⋆ Then, amount will be 2x
We know that,
S.I = Amount - Principal
⋆ Simple Interest = 2x - x = Rs x
⋆ Rate of interest = =
Hence, we get
According to the question,
➛
Cross multiplication,
➛ = T
➡ Time = 16 years
The number of years is 16 years.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Solution :
Here , let us assume that the principal for the simple interest is Rs. x .
Now , the rate of the simple interest is 6 1/4 % per annum .
Rate :
> [ 24 + 1]/4 %
=> 25/4 % per annum .
Assume that the required number of years after the principal doubles to become twice of its amount is t years .
According to the question :
If the principal become twice itself :
=> Original Principal + SI for a certain number of years ] = 2 × Original Principal
=> Original Principal = SI for a certain number of years .
We took the original principal as Rs. x and the time as t
=> x = [ x • t • 25/4 ] / 100
=> x = [ x • t • 25/400 ]
=> x = [ x • t • 1/16 ]
=> 1 = t/16
=> t = 16 years .
Thus , the required time period is 16 years .
This is the answer .
___________________________________________
Answer:
Given :-
Find Out :-
Formula Required :-
Solution :-
⋆ Let, the principle be Rs x
⋆ Then, amount will be 2x
We know that,
S.I = Amount - Principal
⋆ Simple Interest = 2x - x = Rs x
⋆ Rate of interest =
= ![\dfrac{25}{4} \dfrac{25}{4}](https://tex.z-dn.net/?f=%5Cdfrac%7B25%7D%7B4%7D)
Hence, we get
According to the question,
➛![\tt{x =\: \dfrac{x \times T \times 25}{100 \times 4}} \tt{x =\: \dfrac{x \times T \times 25}{100 \times 4}}](https://tex.z-dn.net/?f=%5Ctt%7Bx%20%3D%5C%3A%20%5Cdfrac%7Bx%20%5Ctimes%20T%20%5Ctimes%2025%7D%7B100%20%5Ctimes%204%7D%7D)
➛![\tt{x =\: \dfrac{x \times T \times {\cancel{25}}}{\cancel{100} \times 4}} \tt{x =\: \dfrac{x \times T \times {\cancel{25}}}{\cancel{100} \times 4}}](https://tex.z-dn.net/?f=%5Ctt%7Bx%20%3D%5C%3A%20%5Cdfrac%7Bx%20%5Ctimes%20T%20%5Ctimes%20%7B%5Ccancel%7B25%7D%7D%7D%7B%5Ccancel%7B100%7D%20%5Ctimes%204%7D%7D)
➛![\tt{x =\: \dfrac{x \times T}{16}} \tt{x =\: \dfrac{x \times T}{16}}](https://tex.z-dn.net/?f=%5Ctt%7Bx%20%3D%5C%3A%20%5Cdfrac%7Bx%20%5Ctimes%20T%7D%7B16%7D%7D)
Cross multiplication,
➛![\tt{16x = x × T} \tt{16x = x × T}](https://tex.z-dn.net/?f=%5Ctt%7B16x%20%3D%20x%20%C3%97%20T%7D)
➛
= T
➛![\tt{16 = T} \tt{16 = T}](https://tex.z-dn.net/?f=%5Ctt%7B16%20%3D%20T%7D)
➡ Time = 16 years