1. Insert 6 rational number between − 2 3 and 3 4 .
2. Find two rational number between √3 and 2.
3. Rationalize the denominator of 1 1−√7 . 4. Simplify: 3 √5− √3 . 5. Evaluate: (1296) 1 4 × (1296)
1 2. SHORT ANSWER TYPE QUESTIONS: 1. If = 2 + √2 , check whether + 1 is rational or irrational.
2. Rationalize the denominator: 4√3+5√2 4√3+3√2 .
3. If 5 2−1 − 25 −1 = 2500, find .
4. If 2 = 5 = 10 , then prove that 1 + 1 = 1 .
5.Write the following numbers in form
(i) 0.215
(ii) 0.235 .
LONG ANSWER TYPES QUESTIONS: 1.
Prove that : ( − ) + ( − ) + ( −) + = 1.
2. If √18 − 6√5 = √ − √ , prove that + = 18.
3. If 2a = 3b = 6c then show that
4. If then find the value of .
THIS THE WEEKLY QUESTIONS FOR BRAINLY STUDENT .... SOLVE
2. Find two rational number between √3 and 2.
3. Rationalize the denominator of 1 1−√7 . 4. Simplify: 3 √5− √3 . 5. Evaluate: (1296) 1 4 × (1296)
1 2. SHORT ANSWER TYPE QUESTIONS: 1. If = 2 + √2 , check whether + 1 is rational or irrational.
2. Rationalize the denominator: 4√3+5√2 4√3+3√2 .
3. If 5 2−1 − 25 −1 = 2500, find .
4. If 2 = 5 = 10 , then prove that 1 + 1 = 1 .
5.Write the following numbers in form
(i) 0.215
(ii) 0.235 .
LONG ANSWER TYPES QUESTIONS: 1.
Prove that : ( − ) + ( − ) + ( −) + = 1.
2. If √18 − 6√5 = √ − √ , prove that + = 18.
3. If 2a = 3b = 6c then show that
4. If then find the value of .
THIS THE WEEKLY QUESTIONS FOR BRAINLY STUDENT .... SOLVE
Answers & Comments
Verified answer
Answer:
Consider the problem
2
5
2
45
+3
20
=
2
5
2
3×3×5
+3
5×2×2
=
2
5
2×3
5
+3×2
5
=
2
5
6
5
+6
5
=
2
5
12
5
=6
Answer:
1- We can find any number of rational numbers between two given rational numbers.
To proceed with this, we make the denominators of
3- 481−83216+15532+225
=(34)41−8(63)31+15(25)51+15
=3−8×6+15×2+15
=3−48+30+15
=48−48
=0
short answer
1- in image
2- ,in image
3- Answer : x = 3
Given 52x-1 - 25x-1 = 2500
We know 25 = 52
So replace 25 = 52 we will get
52x – 1 – (52)x – 1 = 2500
⇒ 52x – 1 – 52x – 2 = 2500
⇒ 52x – 1 – 5[(2x – 1)-1] = 2500
⇒ 52x – 1 – (52x – 1)*5 –1 = 2500
⇒ 52x – 1 – (52x – 1)/5 = 2500 → (1)
Let 52x – 1 = a
Equation (1) becomes,
a – a/5 = 2500
⇒ 4a/5 = 2500
⇒ a = (2500 × 5)/4 = 3125
Therefore, 52x – 1 = 3125
⇒ 52x – 1 = 55
⇒ 2x – 1 = 5
⇒ 2x = 6
∴ x = 3
4- in image