Verified answer

Answer:

There are 10 pigs and 15 chickens

Step-by-step explanation:

let c be the chicken and p be the pigs

Creating an equation given from the problem.

Remember that their heads are only 1 so ,

• c + p = 25

Remember also that the legs of a chicken is 2. and the legs of a pig is 4.

• 2c+4p = 70

Solving the system of linear equations:

• c + p = 25

c = 25 - p (1)

2c+4p=70 (2)

Substitute c to the second equation and solve for p

• 2c + 4p = 70
• 2(25-p) + 4p = 70
• 50-2p+4p = 70
• 50+2p = 70
• 2p = 70-50
• 2p = 20
• p = 20/2
• p = 10

Again , substitute the value of p to the first equation

• c = 25-p
• c = 25-10
• c = 15

Therefore , there are 10 pigs and 15 chickens