Answer:

1

Step-by-step explanation:

Given a,b,c are in A.P

⟹2b=a+c

And also x,y,z are in G.P

⟹y=

xz

LHS=x

b−c

.y

c−a

.z

a−b

=x

b−c

.z

a−b

.(

xz

)

c−a

=x

b−c

.z

a−b

.x

2

c−a

.z

2

c−a

=x

2

2b−(a+c)

z

2

2b−(a+c)

=x

0

.z

0

=1