1. I am a multiple of 9. I have two digits. I am odd and a multiple of 5. Who am I? ____________
2. It is a multiple of 12. The sum of its digits is 9. It is between 20 and 50. Who could I be? ______________
3. It is a multiple of 8. It is less than (20+27+9) but greater than (15+10+15). The sum of its digits is 12
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Verified answer
MATH RIDDLE: GUESS THE NUMBER
Answers with Step-by-step explanation:
1. I am a multiple of 9. I have two digits. I am odd and a multiple of 5. Who am I?
Solution:
So we are looking for a number which is both a multiple of 9 and 5. The given clues also emphasized that it is an odd number and it is a two digit number.
If we try to list down the multiples of 9 and 5, the common multiples are 45 and 90. Since we are looking for an odd number, then 45 is the number.
2. It is a multiple of 12. The sum of its digits is 9. It is between 20 and 50. Who could I be?
Solution:
We are looking for a number which is a multiple of 12 that lies between 20 and 50. If we list the numbers down, we have 24, 36 and 48 in the list. Another important clue is the sum of the digits should be 9. Now let us add the digits of each number to find out:
Since only 36 has its digits sum up to 9, the answer is 36.
3. It is a multiple of 8. It is less than (20+27+9) but greater than (15+10+15). The sum of its digits is 12.
Solution:
So we are looking for a multiple of 8. And the range is from 15+10+15 = 40 to 20+27+9 = 53. The multiple of 8 between 40 and 53 is 48 only. This also satisfies the last clue since 4 plus 8 is 12. The answer, thus, is 48.
Learn also about least common multiple (LCM):
brainly.ph/question/4765929
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