1 given the standard form of x-5x^2=10
2 Solve the equation 3(x^2-2)=66
3 what the nature of the roots of 3x^2-x-2=0
4 Find the zeros of 2x^2-x'1=0
5 write the quadratic equation given the roots -3 and 4
3 19
6 Transform the quadratic and slove x + - =
x 14
Brainiest ko ung tamang sagot
2 Solve the equation 3(x^2-2)=66
3 what the nature of the roots of 3x^2-x-2=0
4 Find the zeros of 2x^2-x'1=0
5 write the quadratic equation given the roots -3 and 4
3 19
6 Transform the quadratic and slove x + - =
x 14
Brainiest ko ung tamang sagot
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
2.3(x2−2)=66
Step 1: Simplify both sides of the equation.
3x2−6=66
Step 2: Add 6 to both sides.
3x2−6+6=66+6
3x2=72
Step 3: Divide both sides by 3.
3x2
3
=
72
3
x2=24
Step 4: Take square root.
x=±√24
x=2√6 or x=−2√6
Answer:x=2√6 or x=−2√6
3.