1. Find the sum of the reciprocals of two consecutive integers if the smaller integer is x + 1.
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Answer:
(2x + 5 )/ (x^2 + 5x + 6)
Step-by-step explanation:
smaller = x +2 RECIPROCAL = 1/ (x +2)
larger = x + 2 + 1 + X +3 Reciprocal = 1/( x + 3)
1/(x+2) + 1/(x +3) =
(2x + 5 )/ (x^2 + 5x + 6)