Verified answer

[tex]\huge\rm \blue{\underline{\color{skyblue}{ \: ANSWER:}}}[/tex]

1. v = 331.5 + (0.607T) m/s

v = 331.5 + (0.607 × 38°C) m/s

v = 331.5 + (23.07°C) m/s

[tex] \sf \color{turquoise}v = 354.6 m/s[/tex]

2. v = 331.5 + (0.607T) m/s

v = 331.5 + (0.607 × 10°C) m/s

v = 331.5 + (6.07) m/s

[tex] \sf \color{darkred}v = 337.57m/s[/tex]

Since f= 128 Hz= 128/s

[tex] \: \tt v \: = λf[/tex]

[tex] \tt \frac{337.5 m/s \: \div 2.64}{128/s} [/tex]

3.

[tex] \tt T = \frac{ v \: - \: 331.5 m/s}{0.6} [/tex]

[tex] \tt = \frac{342m/s \: - \: 331.5 m/s}{0.6} [/tex]

[tex] \tt \color{lightgreen}= 17.5°C[/tex]

The speed of sound in air at normal atmospheric pressure and at a temperature of 0 0C or 273 K is 331.5 m/s and the speed of sound increases 0.607 m/s for every Celsius degree rise in air temperature.

Thus, the speed of sound in air at a given temperature is :

v = 331.5 + (0.607T)m/s

v = 331.5 + 0.607 × T of room in °C

where v is the speed/velocity of sound and T is the temperature.

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