Verified answer

1.) To find ordered pairs that satisfy the equation x-2y-4=0, we substitute the given values of x into the equation and solve for y.

When x = 1:

1 - 2y - 4 = 0

-2y - 3 = 0

-2y = 3

y = -3/2

So one ordered pair that satisfies the equation is (1, -3/2).

When x = 2:

2 - 2y - 4 = 0

-2y - 2 = 0

-2y = 2

y = -1

So another ordered pair that satisfies the equation is (2, -1).

Therefore, the two ordered pairs that satisfy the equation x-2y-4=0 are (1, -3/2) and (2, -1).

2.) To find ordered pairs that satisfy the equation 3x+y=6, we substitute the given values of x into the equation and solve for y.

When x = 0:

3(0) + y = 6

y = 6

So one ordered pair that satisfies the equation is (0, 6).

When x = 1:

3(1) + y = 6

3 + y = 6

y = 3

So another ordered pair that satisfies the equation is (1, 3).

Therefore, the two ordered pairs that satisfy the equation 3x+y=6 are (0, 6) and (1, 3).