Answer:

1. To calculate the molality (m) of a solution, you need to know the moles of solute and the mass of the solvent.

First, let's calculate the moles of NaOH:

The molar mass of NaOH (sodium hydroxide) is:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

To find the moles of NaOH, divide the mass (in grams) by the molar mass:

moles of NaOH = 200 g / 40.00 g/mol = 5.00 mol

Next, we need to calculate the mass of the solvent (water) in kilograms. The given mass is 150 g, so we convert it to kilograms:

mass of water = 150 g = 150 g / 1000 = 0.150 kg

Finally, we can calculate the molality using the formula:

molality (m) = moles of solute / mass of solvent (in kg)

molality (m) = 5.00 mol / 0.150 kg = 33.33 mol/kg

Therefore, the molality of the NaOH solution is 33.33 mol/kg.

2. To calculate the molality (m) of a solution, you need to know the moles of solute and the mass of the solvent.

First, let's calculate the moles of H₂SO₄ (sulfuric acid):

The molar mass of H₂SO₄ is:

H: 1.01 g/mol

S: 32.07 g/mol

O: 16.00 g/mol

Molar mass of H₂SO₄ = 2 * (1.01 g/mol) + 32.07 g/mol + 4 * (16.00 g/mol) = 98.09 g/mol

To find the moles of H₂SO₄, divide the mass (in grams) by the molar mass:

moles of H₂SO₄ = 1000 kg / (98.09 g/mol) = 10,187.41 mol

Next, we need to calculate the mass of the solvent (water) in kilograms. The given mass is 5 kg.

Finally, we can calculate the molality using the formula:

molality (m) = moles of solute / mass of solvent (in kg)

molality (m) = 10,187.41 mol / 5 kg = 2,037.48 mol/kg

Therefore, the molality of the H₂SO₄ solution is approximately 2,037.48 mol/kg.