1. A milk can has a radius of 5 cm and a height of 10 cm. How much tin was used in making it?
2. A closed cone model has a radius of 8 cm and a height of 15 cm. Find the amount of material used in making the cone.
3. Teresa has a box made of wood in the shape of a cube whose side is 7 decimeters. She wants to paint it all over in the outside. How much area will be painted?
4. How much gift wrapper is needed to wrap a box 22 cm long, 12 cm wide and 7 cm high?
5. A ball made of rubber has a radius of 10 cm. What is the surface area of the rubber material of which it is made?
kindly answer my question with solution thankyou
Answers & Comments
Answer:
The milk can is made of three parts: the top and bottom circular bases, and the curved side. The formula for the surface area of a cylinder is:
SA = 2πr^2 + 2πrh
where r is the radius and h is the height.
In this case, r = 5 cm and h = 10 cm, so:
SA = 2π(5)^2 + 2π(5)(10)
= 100π + 100π
= 200π cm^2
Therefore, 200π square centimeters of tin were used in making the milk can.
The formula for the surface area of a cone is:
SA = πr^2 + πrs
where r is the radius, s is the slant height, and π is Pi.
In this case, r = 8 cm and h = 15 cm, so we need to first find the slant height s:
s = √(r^2 + h^2)
= √(8^2 + 15^2)
≈ 17.08 cm
Now we can plug in the values to get:
SA = π(8)^2 + π(8)(17.08)
= 64π + 136.1π
= 200.1π cm^2
Therefore, 200.1π square centimeters of material were used in making the cone.
The formula for the surface area of a cube is:
SA = 6s^2
where s is the length of one side.
In this case, s = 7 decimeters, so:
SA = 6(7)^2
= 294 dm^2
Therefore, 294 square decimeters of area will be painted.
The formula for the surface area of a rectangular prism is:
SA = 2lw + 2lh + 2wh
where l, w, and h are the length, width, and height, respectively.
In this case, l = 22 cm, w = 12 cm, and h = 7 cm, so:
SA = 2(22)(12) + 2(22)(7) + 2(12)(7)
= 528 + 308 + 168
= 1004 cm^2
Therefore, 1004 square centimeters of gift wrapper are needed to wrap the box.
The formula for the surface area of a sphere is:
SA = 4πr^2
where r is the radius.
In this case, r = 10 cm, so:
SA = 4π(10)^2
= 400π cm^2
Therefore, the surface area of the rubber material of the ball is 400π square centimeters.
Brainly