1)
A man is thrice as old as his son. After 12 years, he will be twice as old as his son at that time. Find their present ages.
2)
A sum of 500 is in the form of notes of denominations of 5 and 10. If the total nhor of notes is 99. find the number of notes of each type.
A man is thrice as old as his son. After 12 years, he will be twice as old as his son at that time. Find their present ages.
2)
A sum of 500 is in the form of notes of denominations of 5 and 10. If the total nhor of notes is 99. find the number of notes of each type.
Answers & Comments
Verified answer
Answer:
1) answer - After 12 years, he will be twice as old as his son at that time. Find their present ages. ∴ Present age of son is 12 years and Present age of father is = 3x = 3 x 12 = 36 years
2)
Solution
Let the number of 5 rupee notes be x,then
The number of 10 rupee notes =90−x
Then ,according to the question
5x+10(90−x)=500
5x+900−10x=500
5x=400
x=80
There are 80 notes of Rs.5 and 10 notes of Rs.10.
hope it helps you di
please mark as brainlist
Answer:
1.) 36 yrs
2.) 10 Rs.
Step-by-step explanation:
hope this will help you
hii isha didi
thank you I tried to make sandwich of our flag
mera school project tha ye