1. A car travels 6p km in 2 hours. What is the speed of the car? 2. A motorcycle...

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1. A car travels 6p km in 2 hours. What is the speed of the car?

To calculate the speed, let us identify first what are the given.

60 km is the distance which define as the total length between two positions.

2 hours is the time that measured period during which an action, process, or condition exists or continues.

Solution

Using the speed formula:

$\tiny \tt \ Speed \: = \frac{distance}{time} = \frac{60}{2} = 30kph$

Answer: The speed of the car is 30 kilometers per hour (kph)

2. A motorcycle travels at 59 kph. How many kilometers will it travel in 4 hours?

To calculate the distance, let us identify first what are the given.

50 kph is the speed that refers to scalar quantity that refers to "how fast an object is moving."

4 hours is the time that measured period during which an action, process and condition exists or continues.

Solution:

Using the speed formula:

$\tiny \tt \ distance = time \times speed = 50 \times 4 = 200km$

Answer: It will travel 200 km in 4 hours.

3. A train is moving at the speed 80 kph. How many hours will hours will it take for the train to travel 476 km?

To calculate the time, let us identify first what are the given.

476 km is the speed that define as the total length between two positions.

68 kmp is the speed that refers to scalar quantity that refers to "how an object is moving."

Solution:

Using the formula:

$\tiny \tt \ Time \: = \frac{distance}{speed} = \frac{476}{68} = 7 \: hours$

Answer: It will take 7 hours to travel

4. Alfred drives for 1½ hours at 75 kph. Calculate the distance travelled.

Given:

75 kph - speed

Solution:

Using the formula:

$\tiny \tt \ distance = time \times speed = 75 \: kph \: 1 \frac{1}{2} \: hour$

$\tiny \tt \ = 75 \times 1 \frac{1}{2} = 75 \times \frac{3}{2} = \frac{75 \times 3}{2} = \frac{225}{2} = 112 \frac{1}{2} \: km$

$\tt \ Answer: He \: travelled \: 112 \frac{1}{2} \: km.$

5. Rizbil walks at the speed of 50 meters per minute. How many minutes can he walk in 1262½?

Given:

$\tiny \tt \ 50 \: m/min - speed \\ \tiny \tt \ 1 \: 262 \: \frac{1}{2} - distance$

Solution:

Using the formula:

$\tiny \tt \ Time \: = \frac{distance}{speed} = \frac{50}{1 \: 262 \: \frac{1}{2} } = 50 \times \frac{2}{2525} = \frac{100}{2525} \div \frac{25}{25} = \frac{4}{101}$

$\tt \ Answer: He \: can \: walk \: for \: \frac{4}{101} \: min.$

$\tt \color{w} \colorbox{blue}{Catarina Claes}$

sadboy20m Arigatō Catarina ☺️

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