Explanation:

A car starts from rest and picks up at the velocity of 20 m/s-2 in 10 seconds. How do you calculate the displacement and acceleration?

The question as stated makes no sense. I am going to assume that the intended question is, “a car starts from rest and is traveling with a velocity of 20 m/s after 10 seconds. How do you calculate the displacement and acceleration?”

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 0, v = 20m/s and t = 10s. We want to find distance, s, and acceleration, a.

Using equation (4), we find s = (u + v)t/2

s = (0 + 20)(10/2) = 100m

Then from equation (3) we find v = u + at

20 = 0 + 10a so a = 20/10 = 2m/s^2

So the distance covered is 100m and the acceleration is 2m/s^2

Answer:

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.Which of the following statements are true for pure substances? (i) Pure substances contain only one kind of particles (ii) Pure substances may be compounds or mixtures (iii) Pure substances have the same composition throughout (iv) Pure substances can be exemplified by all elements other than nickel