Answer:
distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
where:
x₁ = -7
x₂ = -3
y₁ = 6
y₂ = 6
Plugging in the values, we get:
distance = √[(-3 - (-7))² + (6 - 6)²]
distance = √[4² + 0²]
distance = √16
distance = 4
Therefore, the distance between points A (-7,6) and B (-3,6) is 4 units.
2. To find the distance between points C (8,7) and D (-3,9), we can use the distance formula:
x₁ = 8
y₁ = 7
y₂ = 9
distance = √[(-3 - 8)² + (9 - 7)²]
distance = √[(-11)² + 2²]
distance = √121 + 4
distance = √125
distance = 5√5
Therefore, the distance between points C (8,7) and D (-3,9) is 5√5 units.
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Answer:
distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
where:
x₁ = -7
x₂ = -3
y₁ = 6
y₂ = 6
Plugging in the values, we get:
distance = √[(-3 - (-7))² + (6 - 6)²]
distance = √[4² + 0²]
distance = √16
distance = 4
Therefore, the distance between points A (-7,6) and B (-3,6) is 4 units.
2. To find the distance between points C (8,7) and D (-3,9), we can use the distance formula:
distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
where:
x₁ = 8
x₂ = -3
y₁ = 7
y₂ = 9
Plugging in the values, we get:
distance = √[(-3 - 8)² + (9 - 7)²]
distance = √[(-11)² + 2²]
distance = √121 + 4
distance = √125
distance = 5√5
Therefore, the distance between points C (8,7) and D (-3,9) is 5√5 units.