1. A 24-V storage battery is charged by a current of 12 A for half in hour. How much power is required to change the battery at this rate?
a. 0.12 kW
b. 0.18 kW
c. 0.22 kW
d. 0.29 kW
a. 0.12 kW
b. 0.18 kW
c. 0.22 kW
d. 0.29 kW
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Answer:
P = V×I
P = 24V × 12A
P = 288 Watts
Convert 288 Watts (W) to kilowatts (kW) by dividing to 1000.
288 ÷ 1000 = 0.288 or 0.29kW is the power required to change the battery.
Therefore, the answer is letter D. 0.29kW