1. A 2.0kg book is lifted to 0.8m above the table, how much work is done?
2. Based on problem number 1, how much potential energy is done relative to the table?
YUNG MATINO PO SANA. KAILANGAN KO NA PO NGAYON.
brainliest ko makasagot
2. Based on problem number 1, how much potential energy is done relative to the table?
YUNG MATINO PO SANA. KAILANGAN KO NA PO NGAYON.
brainliest ko makasagot
Add an Answer
More Questions From This User See All
Answers & Comments
1.6kg
Since the weight of the table that left the book included in (2.0kg) which is the measurement of the book.
There it goes.
2.0kgx1000m/800m
Cancel out the same variable (the “m”)
2.0x0.8= 1.6kg
Therefore the weight of book is 1.6kg above lifted by the table.
(The answer is applicable if you are searching for the original weight of the book before it was lifted)
I don’t understand your question why you search for the answer of “work?”. I think it isn’t possible to search for how much work will be done. Hehe but, anyway hope it helps if you have miswritten your question. Hehe
2) Potential energy
2.0kg-1.6kg= 0.4kg
In which the table is steady lifting the book. Therefore the potential energy is 0.4kg while the kinetic energy is 1.6kg.
Hope it helps you super.