To solve these problems, we'll use Euler's formula, which states that for any real number x:

cos x + i sin x = e^(ix)

And to find the powers of complex numbers in polar form, we use De Moivre's theorem:

(r(cos x + i sin x))^n = r^n(cos(nx) + i sin(nx))

Now let's solve the given problems:

1. 6(cos 30° + i sin 30°) =

Since we don't have any powers here, we can simplify the expression directly:

6[cos(30°) + i sin(30°)]

6[(√3/2) + i(1/2)]

= 3√3 + 3i

So the expression equals 3√3 + 3i.

2. 8(cos 270° + i sin 270°) =

Again, we don't have any powers, so we can simplify the expression directly:

8[cos(270°) + i sin(270°)]

8[(0) + i(-1)]

= -8i

So the expression equals -8i.