Answer:
We have, L.H.S.=x3+y3+z3−3xyz
=(x+y+z)(x2+y2+z2−xy−yz−zx) [by poynomial identity]
=21(x+y+z)(2x2+2y2+2z2−2xy−2yz−2zx)
=21[(x+y+z)(x−y)2+(y−z)2+(z−x)2]
Hence proved.
वाहन चलाते समय हेलमेट पहना जरूरी है समजाते हुए आपके मित्र को पत्र लकिए
mera name sam hai only
sam dear nhi
mai 10th pass
or ye Kadapa kha h mubeena
Steps of making the numberSteps of making the number
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Verified answer
Answer:
We have, L.H.S.=x3+y3+z3−3xyz
=(x+y+z)(x2+y2+z2−xy−yz−zx) [by poynomial identity]
=21(x+y+z)(2x2+2y2+2z2−2xy−2yz−2zx)
=21[(x+y+z)(x−y)2+(y−z)2+(z−x)2]
Hence proved.
Answer:
वाहन चलाते समय हेलमेट पहना जरूरी है समजाते हुए आपके मित्र को पत्र लकिए
mera name sam hai only
sam dear nhi
mai 10th pass
or ye Kadapa kha h mubeena
Steps of making the numberSteps of making the number