Answer:
=0.1440.24×100%=60% Q. A 0.24 g of sample of compound of oxygen and boron was found by analysis to contain 0.096 g boron and 0.144 g of oxygen.
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Answer:
=0.1440.24×100%=60% Q. A 0.24 g of sample of compound of oxygen and boron was found by analysis to contain 0.096 g boron and 0.144 g of oxygen.